propositionroutine
Hierarchy reward approximates base acceptance probability
Stage- reward is within below ,
one-sided approximation target for the fixed-precision theorem
Proposition·
prop:hier-reward-target·§4.5 Reward transport and the final deterministic targetStatement (paper)
For every stage,
The vectors satisfy
and their updates are
If is the all-primary copy of a base vertex , then
Consequently there is for which the last upper bound is
strictly less than for every base vertex .
In particular, implies , and
implies .
Every full stage domain has size and admits -bit
addresses.
In plain English
At every stage, , and the reward vectors lie in , equal , and obey the explicit update . At the all-primary copy ar x_l of a base vertex , W_l(ar x_l) underestimates by at most , so some separates (giving ) from (giving ), with stage domains of size and -bit addresses.
Why it's here
This turns the copy-step intertwining of the previous proposition into a reward identity. Each stage's reward vector then tracks the acceptance probability up to an error that shrinks geometrically, so a threshold test at a stage decides the base probability. It also bounds the size and addressing of the domains needed to compute it, which the fixed-precision theorem uses as its deterministic target.
Classified routine:
This follows from the copy-step proposition (prop:hier-copy-step) by algebraic bookkeeping: telescoping the intertwining identity into a reward recursion, then turning the geometric density decay into an error bound and a choice of L = O(B). No new idea is needed beyond that earlier node.
Uses
Used by
Sources
PaperOpen
- Section
- §4.5 Reward transport and the final deterministic target
- Page
- —
- Label
prop:hier-reward-target- Line
sections/hierarchy.tex:647
Leannot aligned
Phase 2 aligns this node to a Lean declaration.