lemmaroutineunresolved_ref
Private odd valuation for each radicand
Lemma·
alg:private-valuations·§8.4 A separate odd valuation for each radicandStatement (paper)
For every there is an integer-valued
valuation of such that
Consequently the classes of are independent in
.
In plain English
For each there is an integer-valued valuation of with and for . Hence the classes of are independent in .
Why it's here
Each radicand gets its own valuation, which sees only to odd order and treats the other as units. The construction splits by the shape of the limiting locus: the plane (orders along irreducible curves ), a general curve (power-series branch at a smooth point), a line, or a hyperbola (simple zeros of ). Since a square has even valuation under every integer-valued valuation, any nonempty product of the is a non-square, which gives independence modulo squares.
Classified routine:
A case-by-case construction of discrete valuations (orders of vanishing along curves or at smooth branch points) that separate the radicands. Independence modulo squares then follows by the standard parity argument: a square has even valuation, as in Kummer-theory independence criteria.
Uses
Nothing else in the paper
Used by
Nothing in the paper
Inside the proof
claimPlane case: order along irreducible Q_ellclaimSimple point on curve away from anchorclaimOther radicands avoid 0 and 4 at s_ellclaimPower-series valuation of order oneclaimSame curve, linear or hyperbola formclaimPrivate valuation in the line caseclaimFractional-linear case gives private simple zeroclaimSubset products of radicands are non-squares
Sources
PaperOpen
- Section
- §8.4 A separate odd valuation for each radicand
- Page
- —
- Label
alg:private-valuations- Line
sections/07-algebra.tex:438
Leannot aligned
Phase 2 aligns this node to a Lean declaration.
Friction
- warnunresolved_refExcluding b=1 uses the unit-circle exclusion equation alg:unit-circle and deletion hypothesis argued in Section 8 text, not a labeled statement.